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Article

Creating Normal Numbers Using the Prime Divisors of Consecutive Integers


Authors

Jean-Marie De Koninck and Imre Kátai


Abstract

For each integer n ≥ 2, let p1 ≤ p2··· ≤ pk be the complete list of the prime factors of a(n):= n(n+1). Consider the function sn : {p1,..., pk} {0, 1} defined by sn(pj)= 0 if pj | n and 1 if pj | n + 1. Then consider the binary number h(n) := sn(p1) ...sn(pk). In an earlier paper, we proved that the number 0.h(2) h(3) h(4) ... is a binary normal number and in fact we proved the more general statement when, for a fixed integer t ≥ 2, we set a(n) := n(n +1) ··· (n + t − 1), thus allowing for the construction of a normal number in base t. Here, we give a much shorter and simpler proof of this result and then we consider a more general result when a(n) is the product of linear functions.


Citation

Koninck, J.M.D. & Kátai, I. (2023). Creating Normal Numbers Using the Prime Divisors of Consecutive Integers. Uniform distribution theory, 18(2), 1-18. https://doi.org/10.2478/udt-2023-0010